1. Laws of Indices
Six rules cover almost every exponent manipulation this course will ask for — all of them consistent extensions of what "repeated multiplication" already means.
a^m x a^n = a^(m+n) (multiplying: ADD exponents)
a^m / a^n = a^(m-n) (dividing: SUBTRACT exponents)
(a^m)^n = a^(mxn) (power of a power: MULTIPLY exponents)
a^0 = 1 (any nonzero base to the 0 power)
a^(-n) = 1/a^n (negative exponent = reciprocal)
a^(1/n) = n-th root of a (fractional exponent = a root)
Worked: simplify (2^3 x 2^5) / 2^4
= 2^(3+5-4) = 2^4 = 16
The fractional-exponent rule is the bridge to Section 2 — a^(1/2) IS
√a, not a separate related idea, which is exactly why surds and indices
are taught as one connected topic rather than two.
2. Simplifying Surds
A surd is an irrational root left in root form (like √12) rather than
converted to a decimal. Simplifying means pulling out the largest perfect-square
factor.
Simplify sqrt(72)
72 = 36 x 2 (36 is the largest perfect-square factor of 72)
sqrt(72) = sqrt(36 x 2) = sqrt(36) x sqrt(2) = 6 x sqrt(2)
= 6 sqrt(2)
Combining surds -- only LIKE surds add directly (same root part):
3 sqrt(2) + 5 sqrt(2) = 8 sqrt(2) -- like sqrt(2), combine
3 sqrt(2) + 5 sqrt(3) = CANNOT combine further -- different
root parts, stays as two separate terms
This mirrors combining "like terms" in ordinary algebra (3x + 5x = 8x, but 3x + 5y stays separate) — surds with the same root part behave exactly like a variable, and surds with different root parts are as unrelated as two different variables.
3. Rationalizing Denominators
A fraction with a surd in the denominator (like 1/√2) is conventionally
rewritten with a rational (non-surd) denominator, by multiplying top and bottom by
the surd itself.
1/sqrt(2) -> multiply top and bottom by sqrt(2):
1/sqrt(2) x sqrt(2)/sqrt(2) = sqrt(2)/2
(Multiplying by sqrt(2)/sqrt(2) = 1 doesn't change the
VALUE, only the form -- sqrt(2) x sqrt(2) = 2, a rational
number, in the denominator.)
1/(3 + sqrt(2)) -> multiply by the CONJUGATE (3 - sqrt(2))
1/(3+sqrt(2)) x (3-sqrt(2))/(3-sqrt(2))
= (3-sqrt(2)) / (3^2 - (sqrt(2))^2)
= (3-sqrt(2)) / (9-2)
= (3-sqrt(2)) / 7
The conjugate trick uses (a+b)(a-b)=a^2-b^2 -- the surd
term SQUARES AWAY entirely, leaving a rational denominator.
4. Logarithm Rules
A logarithm answers "what exponent gives this result?" — it's the inverse operation of exponentiation, and its rules are Section 1's index laws, translated.
log_b(x) = y MEANS THE SAME THING AS b^y = x
Worked: log_2(8) = ? -> "2 to what power gives 8?" -> 3
(check: 2^3 = 8, correct)
log(a x b) = log(a) + log(b) (product -> SUM of logs)
log(a / b) = log(a) - log(b) (quotient -> DIFFERENCE)
log(a^n) = n x log(a) (power -> MULTIPLY out front)
log_b(b) = 1
log_b(1) = 0
Worked: solve for x in 3^x = 81
Take log of both sides: log(3^x) = log(81)
x log(3) = log(81)
x = log(81)/log(3)
-- or, faster, recognize 81 = 3^4 directly -> x=4
The "sum of logs for a product" rule is exactly why logarithms were historically used
to turn multiplication into addition (via log tables) — a detail worth knowing
conceptually, since it's precisely why log(a×b) = log(a) + log(b) and
not some other combination.
Many test-level exponential equations (like 3^x=81) are faster solved by recognizing the base's power directly (81=3^4) than by formally taking logs of both sides — save the log rules for cases where the numbers genuinely don't share a clean common base, which is a smaller fraction of questions than it might first appear.
5. Practice Problems
30 problems, no calculator — Easy, Medium & Tough
Try to recognize clean powers before reaching for logarithm rules. Easy problems should take under 30 seconds each; Medium under 60 seconds; Tough under 90 seconds.
Easy (1–10)
- Simplify: 2³ × 2⁴.
- Simplify: 3⁵ / 3².
- Simplify: (2²)³.
- Evaluate: 5⁰.
- Evaluate: 2⁻³.
- Simplify: √16.
- Simplify √50 (leave in simplest surd form).
- Evaluate: log₂8.
- Evaluate: log₁₀100.
- Simplify: √4 × √9.
1) 2⁷=128. 2) 3³=27. 3) 2⁶=64. 4) 1. 5) 1/8. 6) 4. 7) 5√2. 8) 3 (2³=8). 9) 2. 10) 2×3=6.
Medium (11–20)
- Simplify: (3⁴ × 3²) / 3³.
- Simplify √72.
- Simplify: 2√8 + 3√2.
- Rationalize: 1/√3.
- Evaluate: log₃81.
- Solve for x: 2ˣ = 32.
- Simplify: log(20) + log(5) using the log rules.
- Simplify: (5³)² / 5⁴.
- Simplify: √3 × √12.
- Evaluate: log₅125.
11) 3⁽⁴⁺²⁻³⁾=3³=27. 12) 6√2. 13) 2√8=4√2; 4√2+3√2=7√2. 14) √3/3. 15) 3⁴=81 → 4. 16) 2⁵=32 → x=5. 17) log(20×5)=log(100)=2. 18) 5⁽⁶⁻⁴⁾=5²=25. 19) √36=6. 20) 5³=125 → 3.
Tough (21–30)
- Simplify: √48 + √27 - √12.
- Rationalize: 1/(4 + √2).
- Solve for x: 3ˣ = 243.
- Simplify: log(45) - log(9).
- Simplify: (2⁵ × 2⁻²) / 2⁰.
- Find the value of x if log₂(x) = 5.
- Simplify: (√5 + √3)(√5 - √3).
- Solve for x: 5^(2x-1) = 125.
- Simplify: log₂64 + log₂4 - log₂8.
- Rationalize and simplify: (3+√2)/(3-√2).
21) √48=4√3, √27=3√3, √12=2√3; 4√3+3√3-2√3=5√3. 22) Multiply by (4-√2)/(4-√2): (4-√2)/14. 23) 3⁵=243 → x=5. 24) log(45/9)=log(5). 25) 2⁽⁵⁻²⁻⁰⁾=2³=8. 26) x=2⁵=32. 27) (√5)²-(√3)²=5-3=2. 28) 5³=125 → 2x-1=3 → x=2. 29) 6+2-3=5. 30) Multiply by (3+√2)/(3+√2): (9+6√2+2)/(9-2)=(11+6√2)/7.
6. Knowledge Check
Four quick questions. Expand each to check your answer.
Q1
Why does a^(1/2) equal √a — what connects a fractional exponent to a root?
Why does a^(1/2) equal √a — what connects a fractional exponent to a root?
For the exponent rules to stay consistent, a^(1/2) × a^(1/2) must equal a^(1/2+1/2) = a^1 = a — and the number that, multiplied by itself, gives a is exactly the definition of √a. So a^(1/2) has to equal √a for the "add exponents when multiplying" rule to keep holding true for fractional exponents too.
Q2
Why can 3√2 and 5√2 be combined into 8√2, but 3√2 and 5√3 cannot be combined further?
Why can 3√2 and 5√2 be combined into 8√2, but 3√2 and 5√3 cannot be combined further?
√2 acts as a single, consistent "unit" being counted, exactly like a variable — 3 of that unit plus 5 of the same unit is 8 of it. √2 and √3 are different, unrelated irrational values, the same way x and y are different variables that can't be combined into a single term by simple addition.
Q3
Why does multiplying by the conjugate (3-√2) eliminate the surd from a denominator like (3+√2), when multiplying by √2/√2 alone wouldn't?
Why does multiplying by the conjugate (3-√2) eliminate the surd from a denominator like (3+√2), when multiplying by √2/√2 alone wouldn't?
The conjugate pair (a+b)(a-b) expands to a²-b², which eliminates the cross terms that would otherwise still contain the surd — squaring √2 turns it into the rational number 2. Multiplying just by √2/√2 only works when the denominator IS a lone surd; for a binomial denominator like (3+√2), only the conjugate trick produces the needed cancellation.
Q4
Why does log(a×b) equal log(a) + log(b), rather than log(a) × log(b)?
Why does log(a×b) equal log(a) + log(b), rather than log(a) × log(b)?
A logarithm is fundamentally an exponent, and multiplying two numbers with the same base means ADDING their exponents (Section 1's first index law) — since log(a) and log(b) are exactly those exponents, the exponent of the product a×b is their sum, which is what the logarithm of that product reports.